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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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QUICK MATH HELP!!! TRIANGLE PROBLEM!!
I need to know what the length of 2 sides of an isocolese triangle is when the hypot. is 48.75. Anyone know the formula?
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Posted 2/25/06 1:15 PM  |
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dpli
Daylight savings :)
Member since 5/05 13973 total posts
Name:
D
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Did they give you the measure of one of the angles?
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| Posted 2/25/06 1:18 PM |
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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
its a right isoc. triangle. so 90 and 45 and 45
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| Posted 2/25/06 1:21 PM |
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julz33
i run for bacon
Member since 5/05 20584 total posts
Name:
julz
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
37.47
i did asquared + bsquared = csquared
Message edited 2/25/2006 1:24:56 PM.
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| Posted 2/25/06 1:24 PM |
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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
How do you know that?
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| Posted 2/25/06 1:24 PM |
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dpli
Daylight savings :)
Member since 5/05 13973 total posts
Name:
D
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Use the formula:
Sin 45 = opposite/hypotenuse
So the leg is the opposite side
opposite = hypotenuse x sin 45
opposite = 48.75 x sin 45
opposite = 48.75 x 0.707
opposite = 34.47
If you use a^2 + b^2 = c^2:
2x^2 = 48.75^2
2x^2 = 2376.5625
x^2 = 1188.28
x = 34.47
Message edited 2/25/2006 1:29:30 PM.
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| Posted 2/25/06 1:25 PM |
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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Ok, one more what is 87.75
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| Posted 2/25/06 1:26 PM |
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julz33
i run for bacon
Member since 5/05 20584 total posts
Name:
julz
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
asquared + bsquared = csquared
asquared + bssuared = 48.75squared
asquared + bsquared = 2376.5625
since a and b are the same lengths,
asquared = 1/2 of 2376.56 = 1188.28125
a = 34.471455
b would be the same as a
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| Posted 2/25/06 1:28 PM |
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julz33
i run for bacon
Member since 5/05 20584 total posts
Name:
julz
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Posted by KPtoys
Ok, one more what is 87.75
62.048
62.048 squared + 62.048 squared = 87.75 squared
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| Posted 2/25/06 1:29 PM |
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elyssa222
******
Member since 5/05 1541 total posts
Name:
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Posted by KPtoys
Ok, one more what is 87.75
62.05
Message edited 2/25/2006 1:31:15 PM.
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| Posted 2/25/06 1:30 PM |
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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Umm which one is right
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| Posted 2/25/06 1:31 PM |
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elyssa222
******
Member since 5/05 1541 total posts
Name:
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
i made a mistake...julz was right
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| Posted 2/25/06 1:31 PM |
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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Ok, I think I got it. I must have been absent that day in school!!! I am all flustered right now - lol. THANK YOU!!
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| Posted 2/25/06 1:31 PM |
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dpli
Daylight savings :)
Member since 5/05 13973 total posts
Name:
D
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Posted by KPtoys
Umm which one is right
Julz is right
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| Posted 2/25/06 1:31 PM |
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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Sooo last one what would 60 be?
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| Posted 2/25/06 1:35 PM |
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julz33
i run for bacon
Member since 5/05 20584 total posts
Name:
julz
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Posted by elyssa222
i made a mistake...julz was right
you just had to divie by two
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| Posted 2/25/06 1:35 PM |
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julz33
i run for bacon
Member since 5/05 20584 total posts
Name:
julz
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Posted by KPtoys
Sooo last one what would 60 be?
42.4264
This is fun
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| Posted 2/25/06 1:36 PM |
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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
This whole getting the square thing back down is screwing me up
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| Posted 2/25/06 1:36 PM |
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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Glad I could make you happy today - make you think, You will be happy to know that are helping my DH work... and make money for us - LOL
I appreciate it!
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| Posted 2/25/06 1:37 PM |
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dpli
Daylight savings :)
Member since 5/05 13973 total posts
Name:
D
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Are you studying for something?
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| Posted 2/25/06 1:39 PM |
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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
No, my DH is in the field building something... he calls me and asks me to figure something out for him... me who blows it in the math dept. I look online for the formula. I get the pothag. ther. but then I am like W T F how do I get the square of the a and b once I have what they are as being squared... I still dont get it so if someone could explain it to me that would be GREAT!
BUT then I knew I could come on here and someone would be able to help me!! Thankgoodness for LIF
Message edited 2/25/2006 1:42:24 PM.
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| Posted 2/25/06 1:41 PM |
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dpli
Daylight savings :)
Member since 5/05 13973 total posts
Name:
D
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
Ahhhh
I am a former math teacher, I always enjoy answering these kind of questions. 
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| Posted 2/25/06 1:47 PM |
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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
so once you have c how you get a & b?
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| Posted 2/25/06 1:50 PM |
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julz33
i run for bacon
Member since 5/05 20584 total posts
Name:
julz
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
once you have c, multiply c x c.
Divide that by 2
take the square root
that is the value of A and B (since they are the same)
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| Posted 2/25/06 1:54 PM |
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KPtoys
I'm getting old
Member since 5/05 8688 total posts
Name:
Karen
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Re: QUICK MATH HELP!!! TRIANGLE PROBLEM!!
lol that musta been my problem. I didnt have a sq root key on my calculator
ty
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| Posted 2/25/06 2:00 PM |
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